According to the logarithm definition:
[tex]\log_bc=a\Leftrightarrow b^a=c[/tex]
In this question:
[tex]\begin{gathered} 3.6=6^x \\ which\text{ }is\text{ }the\text{ }same\text{ }as \\ 6^x=3.6 \end{gathered}[/tex]
Then, comparing with the definitionm:
a = x
b = 6
c = 3.6
And, transforming to the log form:
[tex]\begin{gathered} \begin{equation*} \log_bc=a \end{equation*} \\ \log_6(3.6)=x \end{gathered}[/tex]
Answer:
[tex]\operatorname{\log}_{6}(3.6)= x[/tex]
