Question

6. A 64 inch cord is extended from the top of a pole to the ground. If the cord makes a 60 degree angle with the ground, how tall is the pole to the nearest tenth of an inch? 64 in X 600

Answer 1

$32\sqrt[\square]{3=x}$

Explanation

we have a rigth triangle, so we can use sin function

Step 1

Let

hypotenuse=64

angle=60 degrees

opposite side= x

then

$\begin{gathered} \sin \emptyset=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{hypotenuse}\cdot\sin \emptyset=opposite\text{ side} \end{gathered}$

by replacing:

$\begin{gathered} \text{hypotenuse}\cdot\sin \emptyset=opposite\text{ side} \\ 64\cdot\sin (60)=x \\ 64\cdot\frac{\sqrt[]{3}}{2}=x \\ 32\sqrt[\square]{3=x} \end{gathered}$

So, the heingth is 55,4 inches

I hope this helps you