Given:
b) The 1999 Women's World Cup was played at the Rose Bowl on a playing field 116 yards long and 72 yards wide.
The area is given as,
[tex]\begin{gathered} A_1=\text{Length}\times Width \\ =116\times72 \\ =8352\text{ square yd} \end{gathered}[/tex]
The largest field have length 120 yd and width 75 yd,
The area is given as,
[tex]\begin{gathered} A_2=Length\times Width \\ =120\times75 \\ =9000\text{ square yd} \end{gathered}[/tex]
The percentage increase is given as,
[tex]\begin{gathered} \text{Percentage increase=}\frac{A_2-A_1}{A_1}\times100 \\ =\frac{9000-8352}{8352}\times100 \\ =\frac{648}{8352}\times100 \\ =7.7586\text{ } \\ =7.8(\text{nearest tenth of percent)} \end{gathered}[/tex]
Answer: Percentage increase is 7.8 %