please help me find BD. angle A is 30° and BC is 50°

We have that angle BAD is an exterior angle of the circle, then, we have the following general equation:
[tex]\measuredangle BAD=\frac{1}{2}(\hat{BD}-\hat{BC})[/tex]where BD and BC are the measures of their respective arc.
In this case,we have the following:
[tex]\begin{gathered} \measuredangle BAD=30\degree \\ BC=50\degree \end{gathered}[/tex]then, using the equation and solving for BD, we get:
[tex]\begin{gathered} \frac{1}{2}(BD-50)=30 \\ \Rightarrow BD-50=2\cdot30=60 \\ \Rightarrow BD=60+50=110 \\ BD=110\degree \end{gathered}[/tex]therefore, the measure of arc BD is 110 degrees