The number of students have a brother is 17.
The number of students have a sister is 12.
The number of students who donot have any siblings are 5.
The total students are 26.
Let there are x students who have both brother and sister. So number of students with only brother s (17 - x), number of students with sister only is (12 - x).
Determine the number of students have both brother and sister.
[tex]\begin{gathered} 17-x+12-x+x+5=26 \\ -x=26-17-12-5 \\ x=8 \end{gathered}[/tex]So probability for students with both brother and sister is,
[tex]P(\text{ Brother and sister)=}\frac{8}{26}[/tex]Probability for student have sister is,
[tex]P(\text{ sister)=}\frac{12}{26}[/tex]Determine the probability that a student has a brother given that they have a sister.
[tex]\begin{gathered} P\text{ (Brother and sister|sister)=}\frac{P\text{ (Brother and sister)}}{P\text{ (Sister)}} \\ =\frac{\frac{8}{26}}{\frac{12}{26}} \\ =\frac{8}{26}\cdot\frac{26}{12} \\ =\frac{8}{12} \\ =\frac{2}{3} \end{gathered}[/tex]Answer: 2/3