Question

A pile of sand is in the form of a right circular cone of altitude 4m and slant height 7m. What is the weight of the sand, if the sand weighs 50kg/m^3?

Answer 1

h = 4m

slant height = 7m

volume of the cone:

$V\text{ = }\frac{1}{3}\pi r^2h\text{ }$

But first we need to find the radius, as follows:

now the volume of the cone is:

$V\text{ = }\frac{1}{3}\pi(5.74)^2(4)=138.23m^3$

if the sand weighs 50kg per m³, then

50 x 138.23 = 6911.5 kg is the weight of the sand