If a cone has a diameter of 4 I'm and a height of 11.cm, what is the volume of the cone?

Volume of a cone is represented by the following expression:
[tex]\begin{gathered} V=\frac{1}{3}\pi\cdot r^2\cdot h \\ \text{where, } \\ r=\text{radius} \\ \pi=\text{constant=3.1416} \\ h=\text{height} \end{gathered}[/tex]With the information given, we can substitute and find the volume:
[tex]\begin{gathered} V=\frac{1}{3}\cdot\pi\cdot(2)^2\cdot11.5 \\ V=\frac{46}{3}\pi \\ V=48.17cm^3 \\ V\approx48.2^{} \end{gathered}[/tex]