Question

the equation 2x^2+10x+1-=0 has two solutions A and B where A

Answer 1

Given the equation ;

$2x^2+10x+1=0$

The general solution of the equation is :

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

From the given equation ;

a = 2 , b = 10 , c = 1

so,

$\begin{gathered} x=\frac{-10\pm\sqrt[]{10^2-4\cdot2\cdot1}}{2\cdot2}=\frac{-10\pm\sqrt[]{92}}{4} \\ So, \\ x=\frac{-10+\sqrt[]{92}}{4}=-0.102 \\ OR \\ x=\frac{-10-\sqrt[]{92}}{4}=-4.898 \end{gathered}$

So, the solution is :

A = -4.898

B = -0.102