Respuesta :

Since AB and NM are the diameters, we can conclude that E is the central point. Therefore, the angle AEC (Central angle) is equal to the arc.

∠MEA, ∠AEC and ∠NEC are supplementary angles, therefore:

[tex]\begin{gathered} \angle MEA+\angle AEC+\angle NEC=180 \\ 55+\angle AEC+65=180 \\ 120+\angle AEC=180 \\ so\colon \\ \angle AEC=180-120 \\ \angle AEC=60 \\ _{\text{ }}Therefore\colon \\ AC=\angle AEC \\ AC=60 \end{gathered}[/tex]

Answer:

60⁰

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