Question

Write the equation of the circle in standard form. Show all work.

Answer 1

Answer:

$(x-6)^2+(y+3)=7^2$

Explanation:

Here, we want to write the equation of the circle

We have the general form as follows:

$\text{ (x-a)}^2+(y-b)^2=r^2$

(a,b) represents the center of the circle, while r represents the radius of the circle

Re-writing the given equation, we have it that:

$\begin{gathered} (x-6)^2+(y+3)^2\text{ = 4 + 45} \\ (x-6)^2+(y+3)=7^2 \end{gathered}$