Question

Addition and subtraction of algebraic expressions(9x - 1)/6 + (2x -10)/5

Answer 1

To solve this question, follow the steps below.

Step 01: Find the LCM of 5 and 6 (denomitators).

5, 6 | 2

5, 3 | 3

5, 1 | 5

1, 1

The LCM is 2*3*5 = 30

Step 02: Rewrite the fractions using 30 as the denominator.

To do it, divide 30 by the original denominator and multiply the result by the numerator.

$\frac{5\cdot(9x-1)}{30}+\frac{6\cdot(2x-10)}{30}$

Step 03: Solve the expression.

First, since the fractions have the same denominator, you can write them using only one denominator:

$\frac{5\cdot(9x-1)+6\cdot(2x-10)}{30}$

Now, remove the parentheses by solving the multiplications.

$\begin{gathered} \frac{5\cdot9x+5\cdot(-1)+6\cdot2x+6\cdot(-10)}{30} \\ \frac{45x-5+12x-60}{30} \end{gathered}$

Adding like terms:

$\begin{gathered} \frac{45x+12x-5-60}{30} \\ \frac{57x-65}{30} \end{gathered}$

Answer:

$\frac{57x-65}{30}$