Respuesta :

We need to solve the next given expression:

[tex]\lvert4x-1\rvert=6[/tex]

Now, we need to use the next absolute rule:

if lul = a, where a>0

Then, u = a or u = -1

Therefore, we have the next :

[tex]\begin{gathered} 4x-1=6 \\ or \\ 4x-1=-6 \end{gathered}[/tex]

Solve for x . Therefore:

[tex]4x-1=6[/tex][tex]4x=6+1[/tex][tex]x=\frac{7}{4}[/tex]

or

[tex]4x-1=-6[/tex][tex]4x=-6+1[/tex][tex]x=-\frac{5}{4}[/tex]

Hence, x can take the next two values:

[tex]x=-\frac{5}{4},\frac{7}{4}[/tex]

RELAXING NOICE
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