We need to solve the next given expression:
[tex]\lvert4x-1\rvert=6[/tex]Now, we need to use the next absolute rule:
if lul = a, where a>0
Then, u = a or u = -1
Therefore, we have the next :
[tex]\begin{gathered} 4x-1=6 \\ or \\ 4x-1=-6 \end{gathered}[/tex]Solve for x . Therefore:
[tex]4x-1=6[/tex][tex]4x=6+1[/tex][tex]x=\frac{7}{4}[/tex]or
[tex]4x-1=-6[/tex][tex]4x=-6+1[/tex][tex]x=-\frac{5}{4}[/tex]Hence, x can take the next two values:
[tex]x=-\frac{5}{4},\frac{7}{4}[/tex]