Question

answer the following question .

Answer 1

If two lines are perpendicular, then:

$m1\times m2=-1$

From the equation:

$y=-\frac{1}{3}x-5$

We can conclude:

$m1=-\frac{1}{3}$

So:

$\begin{gathered} -\frac{1}{3}\times m2=-1 \\ m2=3 \end{gathered}$

Let:

$(x1,y1)=(0,-3)$

Using the point-slope equation:

$\begin{gathered} y-y1=m2(x-x1) \\ y-(-3)=3(x-0) \\ y+3=3x \\ solve_{\text{ }}for_{\text{ }}y\colon \\ y=3x-3 \end{gathered}$