Respuesta :

Given:

[tex]AB=BC[/tex]

[tex]\begin{gathered} \angle C=2x-5 \\ \angle A=x+10 \end{gathered}[/tex]

Required:

To find the angle A.

Explanation:

We know tha "If two sides of a triangle are equal , then it has equal angles".

Therefore

[tex]\angle C=\angle A[/tex][tex]\begin{gathered} 2x-5=x+10 \\ 2x-x=10+5 \\ x=15 \end{gathered}[/tex]

Now angle A ia,

[tex]\begin{gathered} \angle A=x+10 \\ =15+10 \\ =25\degree \end{gathered}[/tex]

Final Answer:

The option D is correct.

[tex]\angle A=25\degree[/tex]

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