Consider the line y=3/4x +3. Find the equation of the line that is parallel to this line and passed through the point (-8, 6)

Respuesta :

The slopes of two lines parallel to each other is equal. The equation given is

[tex]\begin{gathered} y=\frac{3}{4}x+3 \\ \text{The slope is the coefficient of x.} \\ \text{That means the slope of the parallel line is }\frac{3}{4} \\ \text{If the other line passes through the point (-8, 6), then} \\ U\sin g\text{ the known values which are x, y and m, the other line becomes} \\ y=mx+b \\ 6=\frac{3}{4}(-8)+b \\ 6=-6+b \\ 6+6=b \\ b=12 \\ \text{Having known the values of m and b, the parallel line is now shown as;} \\ y=\frac{3}{4}x+12 \end{gathered}[/tex]

The equation of the parallel line is derived as

y = 3/4x + 12

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