Question

Find the area of the triangle below. Be sure to include the correct unit in your answer. 16yd 6yd 10yd

Answer 1

Consider the figure.

From the triangle ABD, we have,

$BD=\sqrt[]{16^2-6^2}=14.83$

Therefore,

$BC=14.83-10=4.83$

From the traingle ABC, we have,

$AC=\sqrt[]{4.83^2+6^2}=7.7$

Thus, the area of the traingle is,

$\frac{1}{2}\times7.7\times10=38.5$