The question ask to evaluate the expression:
[tex]9^{-\frac{5}{2}}[/tex]Step 1: Factor the number
[tex]9=3^2[/tex]Therefore, the expression becomes:
[tex]\Rightarrow(3^2)^{-\frac{5}{2}}[/tex]Step 2: Apply the exponent rule given to be
[tex](x^a)^b=x^{a\times b}[/tex]Therefore, we have:
[tex]\Rightarrow(3^2)^{-\frac{5}{2}}=3^{2\times-\frac{5}{2}}=3^{-5}[/tex]Step 3: Apply the exponent rule given to be
[tex]x^{-a}=\frac{1}{x^a}[/tex]Therefore, the expression becomes:
[tex]3^{-5}=\frac{1}{3^5}[/tex]Step 4: Calculate
[tex]3^5=243[/tex]Therefore, we have
[tex]\frac{1}{3^5}=\frac{1}{243}[/tex]ANSWER
[tex]9^{-\frac{5}{2}}=\frac{1}{243}[/tex]