Question

I was asked to do this and I don't understand. Given the following balanced equation for the electrolysis of melted aluminum oxide to produce aluminum and oxygen:2Al2O3 --> 4Al + 3O2What is the molar ratio ofaluminum oxide to aluminum ?aluminum oxide to oxygen?aluminum to oxygen?Write your answer as a fraction.

Answer 1

1) Molar ratio. This number shows the amounts in moles of the compound in a reaction. We can also say that this number shows how many moles of the product are formed from a specific reactant.

2) Balance the chemical equation.

$2Al_2O_3\rightarrow4Al+3O_2$

3) Molar ratios

The molar ratio of aluminum oxide (Al2O3) to aluminum (Al).

Al2O3 = there is a 2 in front of this formula.

Al = there is a 4 in front of this formula.

The molar ratio of these two compounds is 2 mol Al2O3: 4 mol Al.

As a fraction

$\frac{2molAl_2O_3}{4molAl_{}}$

The molar ratio of aluminum oxide (Al2O3) to oxygen (O2).

Al2O3 = there is a 2 in front of this formula.

O2 = there is a 3 in front of this formula.

The molar ratio of these two compounds is 2 mol Al2O3: 3 mol O2.

As a fraction

$\frac{2molAl_2O_3}{3molO_2}$

The molar ratio of aluminum (Al) to oxygen (O2).

Al = there is a 4 in front of this formula.

O2 = there is a 3 in front of this formula.

The molar ratio of these two compounds is 4 mol Al: 3 mol O2.

As a fraction

$\frac{4molAl_{}}{3molO_2}$