To do this problem we will use Charles' law. Charles law states that the volume of a given mass of gas varies directly with the absolute temperature of a gas when pressure is kept constant.
Charles law:
[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ V_1:inital\text{ }volume\text{ }(L)=2.00L \\ T_1:initial\text{ }temperature\text{ }(K)=16\degree C \\ V_2:final\text{ }volume\text{ }(L)=6.00L \\ T_2:final\text{ }temperature\text{ }(K)=x \end{gathered}[/tex]By substituting what is given into the formula to determine the unknown we have:
[tex]\begin{gathered} \frac{2.00L}{16\degree C}=\frac{6.00L}{x} \\ \\ x=(6.00L\times16\degree C)\div2.00L \\ x=48\degree C \end{gathered}[/tex]Answer: The final temperature of the gas is 48 degrees celcius.
