Given data:
* The mass of the book is m = 2 kg.
* The height of book A is h_A = 1 m.
* The height of book B is h_B = 1.5 m.
* The height of book C is h_C = 2 m.
Solution:
(a). The gravitational potential energy of book A is,
[tex]U_A=\text{mgh}_A[/tex]
where g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} U_A=2\times9.8\times1 \\ U_A=19.6\text{ J} \end{gathered}[/tex]
Thus, the gravitational potential energy of book A is 19.6 J.
(b). The gravitational potential energy of book B is,
[tex]\begin{gathered} U_B=\text{mgh}_B \\ U_B=2\times9.8\times1.5 \\ U_B=29.4\text{ J} \end{gathered}[/tex]
Thus, the gravitational potential energy of book B is 29.4 J.
(c). The gravitational potential energy of book C is,
[tex]\begin{gathered} U_C=\text{mgh}_C \\ U_C=2\times9.8\times2 \\ U_C=39.2\text{ J} \end{gathered}[/tex]
Thus, the gravitational potential energy of book C is 39.2 J.
