Replace f(x) with y .
[tex]y=6x^5\text{ + 2}[/tex][tex]\begin{gathered} \text{make x the subject of the formular } \\ y-2=6x^5 \\ divide\text{ both sides by 6} \\ \frac{y-2}{6}=x^5 \\ \end{gathered}[/tex][tex]\begin{gathered} To\text{ make x stand alone } \\ \sqrt[5]{\frac{y-2}{6}}\text{ = x} \end{gathered}[/tex]Swap x and y
[tex]\sqrt[5]{\frac{x-2}{6}}\text{ = y}[/tex]Therefore,
[tex]f^{-1}(x)\text{ = }\sqrt[5]{\frac{x-2}{6}}[/tex]