Given
[tex]log3a+log4a-2loga[/tex]We can find the antilog below;
Explanation
[tex]\begin{gathered} log3a+log4a-2loga \\ =log3a+log4a-loga^2 \\ =log(\frac{3a\times4a}{a^2}) \\ =log12 \end{gathered}[/tex]Therefore, the antilog becomes of the above becomes;
[tex]antilog(log12)=12[/tex]Answer: 12
