Question

Hello, how do you find the slope of the line that contained the points (6, -10) and (-18, 6)

Answer 1

Remember that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

In this problem we have

(6, -10) and (-18, 6)

so

(x1,y1)=(6,-10)

(x2,y2)=(-18,6)

substitute in the formula

$\begin{gathered} m=\frac{6-(-10)}{-18-6} \\ m=\frac{6+10}{-24} \\ \\ m=\frac{16}{-24} \end{gathered}$

simplify

$m=-\frac{16}{24}=-\frac{4}{6}=-\frac{2}{3}$

the slope is -2/3