Respuesta :

Recall that we can factorize any polynomial as:

[tex]P(x)=k(x-a)(x-b)...(x-n),[/tex]

where k is a constant and a,b,...n are the root of the polynomial.

Therefore, a polynomial function with the real zeros -3,0, and 3 is:

[tex]f(x)=k(x-3)(x-0)(x+3).[/tex]

k can be any constant, therefore, we can set k=1.

Answer:

[tex]f(x)=x(x+3)(x-3).[/tex]

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