Question

The circle below is centered at (10, 4) and has a radius of 4. What is itsequation?A. (x-10)2 + (y-4)2 = 16O B. (x-4)2 + (x-10)2 = 4C. (x-4)2 + (y-10)2 = 16D. (x-10)2+(y-4)2 = 4

Answer 1

SOLUTION

The general form for the equation of a circle is given as

$(x-a)^2+(y-b)^2=r^2_{}$

where the center of the circle is (a,b) and the radius r

Given a center (10,4) and r=4

The equation of the circle becomes

$\begin{gathered} a=10,b=4,r=4 \\ (x-10)^2+(y-4)^2=4^2 \end{gathered}$

Then the equation becomes

$(x-10)^2+(y-4)^2=16$

TherefThe right option is A