In order to solve this system using substitution, we can use the value of y from the second equation in the first one. So we have that:
[tex]\begin{gathered} \begin{cases}3x+2y=7 \\ y=-3x+11\end{cases} \\ 3x+2\cdot(-3x+11)=7 \\ 3x-6x+22=7 \\ -3x=7-22 \\ -3x=-15 \\ 3x=15 \\ x=\frac{15}{3} \\ x=5 \\ \\ y=-3\cdot5+11 \\ y=-15+11 \\ y=-4 \end{gathered}[/tex]
So the solution for this system is (5, -4), therefore the correct option is the second one.
