Question

Find the area of a sector with a central angle of 170° and a radius of 17 millimeters. Round to the nearest tenth. 857.5 mm2100.9 mm2428.7 mm225.2 mm2

Answer 1

For use to be able to determine the area of a sector, we will be using the following formula:

$\text{ Are of Sector = }(\frac{\Theta}{360^{\circ}})\pi r^2$

We get,

$\text{ Are of Sector = }(\frac{\Theta}{360^{\circ}})\pi r^2$$\text{= }(\frac{170^{\circ}}{360^{\circ}})(3.1416)(17)^2$$\text{= }(0.4722)(3.1416)(289)$$\text{Area of Sector = }428.72095728\text{ }\approx428.7\text{ mm}^2$

Therefore, the answer is 428.7 mm²