Since the relationship is linear, we will solve it as follows:
*We are given two points, we will find the slope:
[tex]m=\frac{57.88-35.13}{33-20}\Rightarrow m=\frac{7}{4}[/tex]*Now, we replace this slope and one of the points in the following expression:
[tex]y-y_1=m(x-x_1)[/tex]Now, we replace:
[tex]y-35.13=\frac{7}{4}(x-20)\Rightarrow y-35.13=\frac{7}{4}x-35[/tex][tex]\Rightarrow y=\frac{7}{4}x+0.13[/tex]Now, we replace the 27 HCF in the expression and solve for the cost:
[tex]y=\frac{7}{4}(27)+0.13\Rightarrow y=47.38[/tex]So, the cost for 27 HCF is $47.38.