Question

How many combinations are possible assume the items are distinct 7 items chosen 5 times

Answer 1

SOLUTION:

Case: Combination

Method:

distinct 7 items chosen 5 times

Selecting 5 from 7 items is:

$\begin{gathered} 7C_5 \\ \frac{7!}{(7-5)!5!} \\ \frac{7!}{2!\times5!} \\ \frac{7\times6\times5!}{2\times1\times5!} \\ \frac{7\times6}{2\times1} \\ \frac{42}{2} \\ =21 \end{gathered}$

Final answer:

There are 21 ways 5 items can be selected from 7 distict items