Question

$\sqrt[3]{32x {}^{7}y ^{4} }$??? help please

Answer 1

$\sqrt[3]{32x^7y^4}$

we will simplify the expression above

$\sqrt[3]{(8)\cdot(4)\cdot x^6\cdot x^{}\cdot y\cdot y^3}$

then we have

$\sqrt[3]{8x^6y^3}\cdot\sqrt[3]{4xy}$

The expression simplified is

$2x^2y\sqrt[3]{4xy}$