I need help explaining this problem or something similar to it!!

Given:
The area of the triangle is 14 square inches.
The perpendicular (horizontal) height of the triangle is 7 inches.
To find:
The length of the shortest side.
Explanation:
Using the formula of the area of the triangle is,
[tex]A=\frac{1}{2}\times b\times h[/tex]Substituting the values we get,
[tex]\begin{gathered} 14=\frac{1}{2}\times b\times7 \\ b=\frac{14\times2}{7} \\ b=4inches \end{gathered}[/tex]Final answer:
The area of the triangle is 4 inches.