length of the shorter side is 12cm
Explanation:let one of the side of th rectangle = x
six times this side = 6x
Another side is 6cm shorter than six times the previous side
this side = 6x - 6
The perimeter of a rectangle = 2(length + width)
let the unknown side = width = x
let the length = 6x - 6
The perimeter of the triangle is given as 156 cm
Perimeter = 2(6x - 6 + x)
156 = 2(6x - 6 + x)
solve for x:
156 = 2(7x - 6)
divide both sides by 2:
[tex]\begin{gathered} \frac{156}{2}=2(\frac{7x -6}{2}) \\ 78\text{ = 7x - 6} \end{gathered}[/tex][tex]\begin{gathered} \text{Add 6 to both sides:} \\ 78\text{+ 6 = 7x } \\ 84\text{ = 7x} \end{gathered}[/tex][tex]\begin{gathered} \text{divide both sides by 7:} \\ \frac{84}{7}\text{ = }\frac{7x}{7} \\ x\text{ = 12} \end{gathered}[/tex]The width = x = 12
The length = 6x - 6 = 6(12) - 6
The length = 66
From the above, we see the length of the shorter side is 12cm