Let the perimiter of the square P
Statement 1
The perimeter of the square is greater than 122 inches
This can be expressed in inequality as
[tex]P>122[/tex]Statement 2
The perimeter of the square is less than 134 inches
This can be expressed in inequality as
[tex]P<134[/tex]Since P = 4S, hence
[tex]4s>122,4s<134[/tex]Solving for s gives
[tex]\begin{gathered} 4s>122 \\ \Rightarrow s>\frac{122}{4} \\ \Rightarrow s>30.5 \end{gathered}[/tex]Aslo
[tex]\begin{gathered} 4s<134 \\ \Rightarrow s<\frac{134}{4} \\ \Rightarrow s<33.5 \end{gathered}[/tex]Hence
[tex]s>30.5,s<33.5[/tex]Combining the inequalities gives
[tex]30.5[tex]\text{.}[/tex]