Given:
[tex]6^{-x+2}=23[/tex]
To find:
The solution
Explanation:
Taking log on both sides,
[tex]log\left(6^{-x+2}\right)=log\left(23\right)[/tex]
Solving for x, we get
[tex]\begin{gathered} (-x-2)log(6)=log(23) \\ -x-2=\frac{log(23)}{log(6)} \\ -x-2=1.74995 \\ -x=2+1.74995 \\ x=-3.74995 \\ x\approx-3.750 \end{gathered}[/tex]
Therefore, the value of x is -3.750.
Final answer:
The value of x is -3.750.
