Question

Two pools are being filled with water. To start, the first pool had 1700 liters of water and the second pool had 1271 liters of water. Water is being added to the first pool at a rate of 26 liters per minute. Water is being added to the second pool at a rate of 37 liters per minute.Let x be the number of minutes water has been added.(questions included in the photo)

Answer 1

(a) It is given that the initial amount of water in the first pool is 1700 liters, and water is been added at a rate of 26 liters per minute.

Hence, after x minutes, the amount of water added to the first pool will be:

$26x$

Since there is an initial amount of water, 1700 liters in the first pool, it follows that the amount of water in the first pool after x minutes is:

$26x+1700$

It is given that the initial amount of water in the second pool is 1271 liters, and water is been added at a rate of 37 liters per minute.

Following the same procedure as the first pool, the amount of water in the second pool after x minutes is:

$37x+1271$

(b) To find the equation when the two pools will have the same amount of water, equate the expressions of the amounts of water for the pools:

$26x+1700=37x+1271$

Answers:

(a) The amount of water in the first pool (in liters) after x minutes = 26x+1700.

The amount of water in the second pool (in liters) after x minutes = 37x+1271

(b) The equation that shows when the two pools would have the same amount of water is 26x+1700=37x+1271.