Question

The circle has center O, and its radius is 9 in. Given that m

Answer 1

solution

For this case we can do the following:

$AB=2\pi r(\frac{x}{360})=2\pi\cdot9in(\frac{40}{360})=2\pi=6.283\text{ in}$

And then the lenght of the ARC ACB would be:

$\text{ACB}=2\pi(9)-2\pi=2\pi(9-1)=16\pi=50.265in$

Final answer 16 pi