Question

y= -x^3+5x-2for this equation state the degreeleading coefficient # of real zeros# of imaginary zerosand the end behavior

Answer 1

1) The leading coefficient = -1

2) Real Zero

A real zero makes the function to be equal to zero

Hence

$\begin{gathered} Afactorofy=-x^3+5x-2\text{ is} \\ x-2 \end{gathered}$

$\frac{-x^3+5x-2}{(x-2)}$$=-x^2-2x+1$

The zeroes are three in number

3) there