Select the correct answer from each drop-down menu.In the first box it’s either (equal to) or (not equal to)In the Second box it’s either (are) or (are not)

Select the correct answer from each dropdown menuIn the first box its either equal to or not equal toIn the Second box its either are or are not class=

Respuesta :

To find h(k(x)), we have to replace the x-variable of h(x) with the function k(x).

[tex]\begin{gathered} h(k(x))=5(\sqrt[]{5x+1})^2-1=5(5x+1)-1=25x+5-1 \\ h(k(x))=25x+4 \end{gathered}[/tex]

Then, find k(h(x)) using the same process.

[tex]\begin{gathered} k(h(x))=\sqrt[]{5(5x^2-1)+1}=\sqrt[]{25x^2-5+1} \\ k(h(x))=\sqrt[]{25x^2-4} \end{gathered}[/tex]

As you can observe, the functions obtained are not equal.

Therefore, h(k(x)) is not equal to k(h(x)).

Also, the functions h and k are not inverse functions because the coefficient 5 would be as a denominator.

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