Question

-6=61–2 – h) + 3 + j; use h = 3, and j = 6

Answer 1

For this case we have the following expression given:

$\frac{-6}{6(-2-h)}+3+j\text{ , h= }3\text{, j=6}$

We can begin doing this:

$\frac{-6}{-6(2+h)}+3+j$

We can cancel -6 and we got:

$\frac{1}{2+h}+3+j$

Now we can replace h=3 and j= 6 and we got:

$\frac{1}{2+3}+3+6=\text{ }\frac{1}{5}+9=\text{ }\frac{46}{5}$