Question

if X and A are counting numbers is X over negative A (x^-a) less than or greater than 1 ?

Answer 1

X & A are counting numbers. This means that a is a number that comes after x just like 2 comes after 1: a > x

Let's assume that x = 1 & a = 2

$x^{-a}\Rightarrow1^{-2}=\frac{1}{1^2}=1$

If x = 2 & a = 3, we have:

$x^{-a}\Rightarrow2^{-3}=\frac{1}{2^3}=\frac{1}{8}$

If x = 3 & a = 4, we have:

$x^{-a}\Rightarrow3^{-4}=\frac{1}{3^4}=\frac{1}{81}$

Except for the first scenario where x = 1 & a = 2 where we got x ^(-a) equal to 1, for every other subsequent value, we will obtain values less than 1