[tex]f(x)=3x^3+x^2-20x+12[/tex]
To determine whether (x + 3) is a factor, let's equate it to zero and solve for x.
[tex]\begin{gathered} x+3=0 \\ x+3-3=0-3 \\ x=-3 \end{gathered}[/tex]
So, let's assume that x = -3. If f(x) = 0 at x = - 3, then (x + 3) is a factor of the polynomial. Let's check.
Replace "x" in the polynomial by -3.
[tex]f(-3)=3(-3)^3+(-3)^2-20(-3)+12[/tex]
Then, simplify.
[tex]f(-3)=-81+9+60+12[/tex][tex]f(-3)=0[/tex]
Since f(x) = 0 when x = -3, then yes, (x + 3) is a factor of the polynomial.
Answer:
f(-3) = 0; yes, the binomial (x + 3) is a factor of the polynomial. (Option 2)