Given:
Principal(P)= $8000 (Initial value)
rate(r) =0.07
time(t) = 1
n = 1 (number of time the interest is compounded)
Using the formula below:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Substitute the values and evaluate.
[tex]A=8000(1+\frac{0.07}{1})^{1\times1}[/tex][tex]=8000(1+0.07)[/tex][tex]=8000(1.07)[/tex][tex]=8560[/tex]Therefore, the amount of money after t = 1 year is $8560.