Respuesta :

Step 1

State the formula for the variance

[tex]S^2=\frac{n(\sum ^{}_{}x^2)-(\bar{\sum ^{}_{}x})^2}{n(n-1)}[/tex][tex]S^2=\frac{10(6750)-(240)^2}{10(10-1)}[/tex][tex]\begin{gathered} S^2=\frac{67500-57600}{10(9)} \\ S^2=\frac{9900}{90}=110 \end{gathered}[/tex]

Step 2

Find the standard deviation

[tex]\begin{gathered} S=\sqrt[]{\text{Variance}} \\ S=\sqrt[]{110} \\ S=10.48808848 \\ S\approx10.49 \end{gathered}[/tex]

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