Circle R has a diameter ST with endpoints at S(4,5) and T (-2,-3).

Given
[tex]\begin{gathered} S(4,5) \\ T(-2,-3) \end{gathered}[/tex]Solution
Diameter is 10
Radius is 5
The Circumference
[tex]\begin{gathered} =2\pi r \\ \\ =2\times\pi\times5 \\ =10\pi \\ =31.42 \\ \end{gathered}[/tex]The area of the circle
[tex]\begin{gathered} =\pi r^2 \\ =\pi\times5^2 \\ =25\pi \\ =78.54 \end{gathered}[/tex]