0.92M
The formula for calculating the molarity of sodium chloride is given as:
[tex]\begin{gathered} Molarity=\frac{moles}{volume} \\ Molarity=\frac{2.3moles}{2.5L} \\ Molarity=0.92M \end{gathered}[/tex]
Hence the molarity of 2.3 moles of sodium chloride in 2.5 L of solution is 0.92M