Constants for waterHvap40.65 kJ/mol-285.83 kJ/mol6.03 kJ/mol4.186 J/g°CAHAHfusionspecific heatmolar mass 18.02 gHow much energy is consumed by thawing 4.3 g ice?

Constants for waterHvap4065 kJmol28583 kJmol603 kJmol4186 JgCAHAHfusionspecific heatmolar mass 1802 gHow much energy is consumed by thawing 43 g ice class=

Respuesta :

INFORMATION:

Is given that

And we must find how much energy is consumed by thawing 4.3 g ice

STEP BY STEP EXPLANATION:

To find it, we need to multiply the mass of the ice by the Hfusion

[tex]4.3g\times6.03\frac{kJ}{mol}[/tex]

Since we need the energy, the answer must be in kJ. So, we need to use the molar mass to obtain the answer in kJ

[tex]4.3g\times\frac{1mol}{18.02g}\times6.03\frac{kJ}{mol}[/tex]

Finally, when we simplify the expression, the answer will be in kJ

ANSWER:

A. 4.3 g x 1 mol/18.02 g x 6.03 kJ/mol

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