ANSWER
[tex]f(2)\ne0[/tex]
The binomial is not a factor of the polynomial
EXPLANATION
Given;
Substitute the value of x;
[tex]\begin{gathered} f\left(x\right)=2x^3+x^2-5x+2 \\ x-2=0 \\ x=2 \end{gathered}[/tex]
Now, find f(2);
[tex]\begin{gathered} f(2)=2\times2^3+2^2-5\times\:2+2 \\ =16+4-10+2 \\ =12 \end{gathered}[/tex]
Hence, since;
[tex]f(2)\ne0[/tex]
The binomial is not a factor of the polynomial.
