2 night stay with 3 meals and cost $195.
3 night stay with 5 meals and costs $300.
Based on the given information, we have
[tex]\begin{gathered} 2x+3y=195 \\ 3x+5y=300 \end{gathered}[/tex]Let's isolate x in the first equation
[tex]\begin{gathered} 2x+3y=195 \\ 2x=195-3y \\ x=\frac{195}{2}-\frac{3y}{2} \end{gathered}[/tex]Then, we combine the new equation with the second one
[tex]\begin{gathered} 3(\frac{195}{2}-\frac{3y}{2})+5y=300 \\ \frac{585}{2}-\frac{9y}{2}+5y=300 \\ \frac{-9y+10y}{2}=300-\frac{585}{2} \\ \frac{y}{2}=\frac{600-585}{2} \\ \frac{y}{2}=\frac{15}{2} \\ y=15 \end{gathered}[/tex]Now, we find x
[tex]\begin{gathered} x=\frac{195}{2}-\frac{3\cdot15}{2} \\ x=\frac{195}{2}-\frac{45}{2} \\ x=\frac{150}{2} \\ x=75 \end{gathered}[/tex]