Dylan gets his pictures developed at Photo-Phast. Photo-First uses the equation C = $0.15 p to calculate = the cost, C, of p photographs. Anne gets her pictures developed at Quick-Pix. Quick-Pix uses the equation C = $0.10 p + $1.20 to calculate their charges. Dylan and Anne paid the same amount of money for their pictures. How many pictures did they get developed? 5 photos 24 photos 36 photos 120 photos

Dylan gets his pictures developed at PhotoPhast PhotoFirst uses the equation C 015 p to calculate the cost C of p photographs Anne gets her pictures developed a class=

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Answer:

B 24 pictures

Explanation:

Given the following

Cost of Dylan picture C = $0.15p

Cost of Anne picture C = $0.10p + $1.20

Since Dylan and Anne paid the same amount of money then;

$0.15p = $0.10p + $1.20

Subtract $0.10 from both sides

$0.15p - $0.10p = $0.10p + $1.20 - $0.10p

$0.05p = $1.20

p = 1.20/0.05

p = 24

Hence the amount of pictures developed is 24 pictures

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