The given function is a logarithmic function:
[tex]y=\log (x-2)+1[/tex]
The domain of a logarithmic function can be found using the fact that the argument of the logarithm must be greater than zero.
Notice that the argument here is x-2. Hence, the domain is found by solving for x when x-2>0:
[tex]\begin{gathered} x-2>0 \\ \text{Add 2 to both sides of the inequality:} \\ x-2+2>0+2\Rightarrow x>2 \\ \text{Write the inequality in interval notation:} \\ (2,\infty) \end{gathered}[/tex]
Hence, the domain of the function is (2,∞).
Recall that the Range of any Logarithmic Function is all real numbers.
Since the given function is a logarithmic function, it follows that the range of the given function is all real numbers.
Option B is the correct answer.